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(F)=F^2+11F-24
We move all terms to the left:
(F)-(F^2+11F-24)=0
We get rid of parentheses
-F^2+F-11F+24=0
We add all the numbers together, and all the variables
-1F^2-10F+24=0
a = -1; b = -10; c = +24;
Δ = b2-4ac
Δ = -102-4·(-1)·24
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-14}{2*-1}=\frac{-4}{-2} =+2 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+14}{2*-1}=\frac{24}{-2} =-12 $
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